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$ABCD$ is a parallelogram such that $AF = 7$ cm, $FB = 3$ cm and $EF = 4$ cm, length $FD =$ equals
- (a)$\frac{21}{4}$ cm
- (b)$\frac{12}{7}$ cm
- (c)$\frac{28}{3}$ cm
- (d)$5.5$ cm
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(A) $\frac{21}{4}$ cm
ABCD is a parallelogram such that AF = 7 cm, FB = 3 cm and EF = 4 cm, length FD = equals
CBSE Class 10 Maths PYQ · Triangles · Similarity with Triangles · 1 Mark · March 2026 · Standard
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