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A vertical pole of height $10\text{ m}$ casts a shadow of $15\text{ m}$ on the ground and at the same time, a tower casts a shadow of $45\text{ m}$ on the ground. Find the height of the tower.
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$\because \Delta ABC \sim \Delta PQR$ [$\frac{1}{2}$ mark]
$\therefore \frac{10}{PQ} = \frac{15}{45} \Rightarrow PQ = 30$
Height of the tower $= 30\text{ m}$ [$1\frac{1}{2}$ marks]
$\therefore \frac{10}{PQ} = \frac{15}{45} \Rightarrow PQ = 30$
Height of the tower $= 30\text{ m}$ [$1\frac{1}{2}$ marks]