191
A vertical pole of height $10 \text{ m}$ casts a shadow of $15 \text{ m}$ on the ground and at the same time, a tower casts a shadow of $45 \text{ m}$ on the ground. Find the height of the tower.
Show SolutionHide Solution↓
Solution: (a)
$\because \Delta ABC \sim \Delta PQR$
$\therefore \frac{10}{PQ} = \frac{15}{45} \Rightarrow PQ = 30$
Height of the tower $= 30 \text{ m}$
$\because \Delta ABC \sim \Delta PQR$
$\therefore \frac{10}{PQ} = \frac{15}{45} \Rightarrow PQ = 30$
Height of the tower $= 30 \text{ m}$