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To protect plants from heat, a shed of iron rods covered with green cloth is made. The lower part of the shed is a cuboid mounted by semi-cylinder as shown in the figure. Find the area of the cloth required to make this shed, if dimensions of the cuboid are $14$ m $\times 25$ m $\times 16$ m
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Sol. Area of cloth required to cover four walls $= 2(14 \times 16 + 25 \times 16)$ (I) (1 Mark)
$= 1248$ m$^2$
Radius $= \frac{14}{2} = 7$ m
Area of cloth required to cover cylindrical part $= \frac{22}{7} \times 7 \times 25 + \frac{22}{7} \times 7^2$ (II) (1 Mark)
$= 704$ m$^2$ (III) ($\frac{1}{2}$ Mark)
$\therefore$ Area of total cloth required $= 1248 + 704 = 1952$ m$^2$ (IV) ($\frac{1}{2}$ Mark)
$= 1248$ m$^2$
Radius $= \frac{14}{2} = 7$ m
Area of cloth required to cover cylindrical part $= \frac{22}{7} \times 7 \times 25 + \frac{22}{7} \times 7^2$ (II) (1 Mark)
$= 704$ m$^2$ (III) ($\frac{1}{2}$ Mark)
$\therefore$ Area of total cloth required $= 1248 + 704 = 1952$ m$^2$ (IV) ($\frac{1}{2}$ Mark)