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The total surface area of a solid hemisphere of diameter '$2d$' is :
- (a)$3 \pi d^2$
- (b)$2 \pi d^2$
- (c)$\frac{1}{2} \pi d^2$
- (d)$\frac{3}{4} \pi d^2$
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(a) $3 \pi d^2$ (1 Mark)
CBSE Class 10 Maths PYQ · Surface Areas & Volumes · Surface Area · 1 Mark · March 2026 · Standard
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