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A wooden article was made by scooping out a hemisphere (of same diameter) from one end of a solid cylinder as shown in the given figure. If the height of the cylinder is $10$ cm and the diameter of the cylinder is $14$ cm, find the total surface area of the remaining wooden article. (Use $\pi = \frac{22}{7}$)
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Solution: Radius of hemisphere = radius of cylinder = $7$ cm
$\text{Surface area of toy} = 2\pi rh + \pi r^2 + 2\pi r^2$ [3 marks]
$= 2 \times \frac{22}{7} \times 7 \times 10 + \frac{22}{7} \times 7 \times 7 + 2 \times \frac{22}{7} \times 7 \times 7$
$= 440 + 154 + 308$ [1 1/2 marks]
$= 902$ sq.cm. [1/2 mark]
$\text{Surface area of toy} = 2\pi rh + \pi r^2 + 2\pi r^2$ [3 marks]
$= 2 \times \frac{22}{7} \times 7 \times 10 + \frac{22}{7} \times 7 \times 7 + 2 \times \frac{22}{7} \times 7 \times 7$
$= 440 + 154 + 308$ [1 1/2 marks]
$= 902$ sq.cm. [1/2 mark]