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A solid is in the form of a right circular cylinder with hemispherical ends. The total height of the solid is $58$ cm and the diameter of the cylinder is $28$ cm. Find the total surface area of the solid.
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Sol. Height of cylindrical part = $58 - 14 - 14 = 30$ cm
Radius of cylindrical as well as hemispherical parts = $14$ cm
TSA of the solid = $4 \times \frac{22}{7} \times (14)^2 + 2 \times \frac{22}{7} \times 14 \times 30$
= $5104 \text{ cm}^2$
Therefore, total surface area of the solid is $5104 \text{ cm}^2$.
Radius of cylindrical as well as hemispherical parts = $14$ cm
TSA of the solid = $4 \times \frac{22}{7} \times (14)^2 + 2 \times \frac{22}{7} \times 14 \times 30$
= $5104 \text{ cm}^2$
Therefore, total surface area of the solid is $5104 \text{ cm}^2$.