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A medicine capsule is in the shape of a cylinder with two hemispheres stuck to each of its ends. The length of the entire capsule is $14 \text{ mm}$ and the diameter of the capsule is $4 \text{ mm}$, find its surface area. Also, find its volume.
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Radius of hemisphere= radius of cylinder = $2 \text{ mm}$
Length of cylindrical part = $14 - 4 = 10 \text{ mm}$.
Surface area of the capsule = CSA of cylinder + $2$(CSA of hemisphere)
$= 2\pi r h + 2(2\pi r^2) = 2 \times \frac{22}{7} \times 2 \times 10 + 2 \times 2 \times \frac{22}{7} \times 2 \times 2$
$= 176 \text{ mm}^2$
Volume of the capsule = volume of cylinder + $2$(volume of hemisphere)
$= \pi r^2 h + 2(\frac{2}{3}\pi r^3) = \frac{22}{7} \times 2 \times 2 \times 10 + 2 \times \frac{2}{3} \times \frac{22}{7} \times 2 \times 2 \times 2$
$= \frac{3344}{21} \text{ mm}^3$ or $159.24 \text{ mm}^3$
Length of cylindrical part = $14 - 4 = 10 \text{ mm}$.
Surface area of the capsule = CSA of cylinder + $2$(CSA of hemisphere)
$= 2\pi r h + 2(2\pi r^2) = 2 \times \frac{22}{7} \times 2 \times 10 + 2 \times 2 \times \frac{22}{7} \times 2 \times 2$
$= 176 \text{ mm}^2$
Volume of the capsule = volume of cylinder + $2$(volume of hemisphere)
$= \pi r^2 h + 2(\frac{2}{3}\pi r^3) = \frac{22}{7} \times 2 \times 2 \times 10 + 2 \times \frac{2}{3} \times \frac{22}{7} \times 2 \times 2 \times 2$
$= \frac{3344}{21} \text{ mm}^3$ or $159.24 \text{ mm}^3$