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A hemispherical bowl of internal diameter $42$ cm contains a liquid. This liquid is to be filled in cylindrical bottles of radius $3$ cm and height $8$ cm. How many bottles are required to empty the bowl ?
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Volume of hemisphere $= \frac{2}{3} \times \pi \times 21 \times 21 \times 21$
Volume of cylinder $= \pi \times 3 \times 3 \times 8$
$\therefore$ Numbers of bottles $= \frac{\text{volume of hemisphere}}{\text{volume of cylinder}} = 85.75$
Hence, $86$ bottles are required to empty the bowl
Volume of cylinder $= \pi \times 3 \times 3 \times 8$
$\therefore$ Numbers of bottles $= \frac{\text{volume of hemisphere}}{\text{volume of cylinder}} = 85.75$
Hence, $86$ bottles are required to empty the bowl