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A cone of height '$h$' and radius '$r$' is surmounted on a hemisphere of same radius. The total surface area of the entire solid will be :
- (a)$\pi rh + \pi r^2$
- (b)$\pi r \sqrt{h^2 + r^2} + \pi r^2$
- (c)$\pi r \sqrt{h^2 + r^2} + 2\pi r^2$
- (d)$\pi r \sqrt{h^2 + r^2} + 3\pi r^2$
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Answer (C) $\pi r \sqrt{h^2 + r^2} + 2\pi r^2$