A carpenter is making a wooden toy (lattu) which is conical in shape and surmounted by a hemisphere. The ratio of the…
CBSE Class 10 Maths PYQ · Surface Areas & Volumes · Ratio · 5 Marks · July 2025 · Standard
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805 Marks · July 2025 · Standard
A carpenter is making a wooden toy (lattu) which is conical in shape and surmounted by a hemisphere. The ratio of the height of the hemisphere and the cone is $3 : 4$. If the radius of the cone and the hemisphere is $2.1$ cm, find the volume of wood required to make this toy. Also, find the area to be painted after making the toy.
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Given r: h = $3:4$ Let $r = 3x, h = 4x$ $\therefore r = 3x = 2.1 \Rightarrow x = 0.7$ Hence $h = 2.8$ cm Volume of wood required to make the toy = Volume of cone + Volume of hemisphere $= \frac{1}{3} \times \frac{22}{7} \times (2.1)^2 \times 2.8 + \frac{2}{3} \times \frac{22}{7} \times (2.1)^3$ $= 32.34 \text{ cm}^3$ Slant height of cone = $\sqrt{(2.1)^2 + (2.8)^2} = 3.5$ cm Total Surface Area = CSA of cone + CSA of hemisphere $= \frac{22}{7} \times 2.1 \times 3.5 + 2 \times \frac{22}{7} \times (2.1)^2$ $= 50.82 \text{ cm}^2$