Following distribution shows the marks of 230 students in a particular subject. If the median marks are 46, then find…

CBSE Class 10 Maths PYQ · Statistics · Find Freuency · 5 Marks · March 2025 · Standard

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825 Marks · March 2025 · Standard

Following distribution shows the marks of 230 students in a particular subject. If the median marks are 46, then find the values of $x$ and $y$.

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Correct table (1 mark). $150 + x + y = 230 \Rightarrow x + y = 80$ (1 mark). Median is 46 $\therefore$ Median class is 40 - 50 ($\frac{1}{2}$ mark). $46 = 40 + [\frac{230/2 - (42+x)}{65}] \times 10$ (1 mark). On solving, we get $x = 34$ and $y = 46$ (1 + $\frac{1}{2}$ marks).