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A life insurance agent insured 100 people of different ages as given in the following distribution table :
Calculate the mean age and median age of the policy holders.
Calculate the mean age and median age of the policy holders.
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Correct table (2 Marks)
Mean $= A + \frac{\Sigma f_i u_i}{\Sigma f_i} \times h$
$= 37.5 + \frac{(-34)}{100} \times 5$ (1 Mark)
$= 35.8$ (1/2 Mark)
Mean age is $35.8$ years
Median $= l + \frac{\frac{n}{2} - cf}{f} \times h$
$= 35 + \frac{50 - 45}{33} \times 5$ (1 Mark)
$= 35.76$ (1/2 Mark)
Median age is $35.76$ years
Mean $= A + \frac{\Sigma f_i u_i}{\Sigma f_i} \times h$
$= 37.5 + \frac{(-34)}{100} \times 5$ (1 Mark)
$= 35.8$ (1/2 Mark)
Mean age is $35.8$ years
Median $= l + \frac{\frac{n}{2} - cf}{f} \times h$
$= 35 + \frac{50 - 45}{33} \times 5$ (1 Mark)
$= 35.76$ (1/2 Mark)
Median age is $35.76$ years