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Three sets of Physics, Chemistry and Mathematics books have to be stacked in such a way that all the books are stored subject-wise and the height of each stack is the same. The number of Physics books is $144$, the number of Chemistry books is $180$ and the number of Mathematics books is $192$. Assuming that the books are of same thickness, determine the number of stacks of Physics, Chemistry and Mathematics books.
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$144 = 2^4 \times 3^2$
$180 = 2^2 \times 3^2 \times 5$
$192 = 2^6 \times 3$
HCF = $2^2 \times 3 = 12$ (1/2)
Number of stacks of Physics Books = $\frac{144}{12} = 12$ (1/2)
Number of stacks of Chemistry Books = $\frac{180}{12} = 15$ (1)
Number of stacks of Mathematics Books = $\frac{192}{12} = 16$ (1)
$180 = 2^2 \times 3^2 \times 5$
$192 = 2^6 \times 3$
HCF = $2^2 \times 3 = 12$ (1/2)
Number of stacks of Physics Books = $\frac{144}{12} = 12$ (1/2)
Number of stacks of Chemistry Books = $\frac{180}{12} = 15$ (1)
Number of stacks of Mathematics Books = $\frac{192}{12} = 16$ (1)