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Three friends plan to go for a morning walk. They step off together and their steps measures $48$ cm, $52$ cm and $56$ cm respectively. What is the minimum distance each should walk so that each can cover the same distance in complete steps ten times?
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$48 = 2^4 \times 3, 52 = 2^2 \times 13, 56 = 2^3 \times 7$
LCM $= 2^4 \times 3 \times 13 \times 7 = 4368$
$\Rightarrow$ Minimum distance each walked in complete steps ten times $= 43680$ cm
LCM $= 2^4 \times 3 \times 13 \times 7 = 4368$
$\Rightarrow$ Minimum distance each walked in complete steps ten times $= 43680$ cm