113
Find the smallest number that is divisible by each of $8, 9$ and $10$.
Show SolutionHide Solution↓
$$\begin{aligned}& 8 = 2^3 \\ & 9 = 3^2 \\ & 10 = 2 \times 5 \\ & LCM (8, 9, 10) = 2^3 \times 3^2 \times 5 = 360 \\ & \therefore\end{aligned}$$ smallest number divisible by each $8, 9$ and $10$ is $360$.