59
Check whether there is any natural number 'n' for which $(14)^n$ ends with the digit '0' or '5'.
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$(14)^n = 2^n7^n$
as it does not have $5$ as the prime factor
Hence, it cannot end with the digit $0$ or $5$
as it does not have $5$ as the prime factor
Hence, it cannot end with the digit $0$ or $5$