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A school has invited $42$ Mathematics teachers, $56$ Physics teachers and $70$ Chemistry teachers to attend a Science workshop. Find the minimum number of tables required, if the same number of teachers are to sit at a table and each table is occupied by teachers of the same subject.
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HCF $(42, 56, 70) = 14$
Minimum number of tables required $= \frac{42}{14} + \frac{56}{14} + \frac{70}{14}$
$= 3 + 4 + 5 = 12$
Minimum number of tables required $= \frac{42}{14} + \frac{56}{14} + \frac{70}{14}$
$= 3 + 4 + 5 = 12$