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The value of $k$ for which the roots of the quadratic equation $6x^2 + 4kx + k = 0$ are real and equal, is
- (a)$0$
- (b)$\frac{3}{4}$
- (c)$\frac{-3}{2}$
- (d)$\frac{2}{3}$
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Ans: (A) $0$
CBSE Class 10 Maths PYQ · Quadratic Equations · Nature of Roots · 1 Mark · March 2025 · Basic
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