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The value of $k$ for which the equation $2kx^2 - 6x + 3 = 0$ has real and equal roots, is:
- (a)$\frac{3}{2}$
- (b)$-\frac{3}{2}$
- (c)$\frac{1}{2}$
- (d)$2$
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Answer: (A) $\frac{3}{2}$
The value of k for which the equation 2kx2 - 6x + 3 = 0 has real and equal roots, is:
CBSE Class 10 Maths PYQ · Quadratic Equations · Nature of Roots · 1 Mark · March 2026 · Basic
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