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If $x = \sqrt{3}$ is a solution of the equation $ax^2 + \sqrt{3}x - 12 = 0$, then
- (a)$a = 3$
- (b)$a = 2$
- (c)$a = 1$
- (d)$a = \sqrt{3}$
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Answer: (A) $a = 3$
CBSE Class 10 Maths PYQ · Quadratic Equations · verify the solution of quadratic equation · 1 Mark · March 2026 · Basic
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