100
Express $\frac{24}{18-x} - \frac{24}{18+x} = 1$ as a quadratic equation in standard form
and find the discriminant of the quadratic equation, so obtained. Also,
find the roots of the equation.
and find the discriminant of the quadratic equation, so obtained. Also,
find the roots of the equation.
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Ans.
(A) Given equation can be written as
$24(18 + x) - 24(18 - x) = 324 - x^2$ (1 Mark)
i.e., $x^2 + 48x - 324 = 0$ (1 Mark)
$D = 48^2 - 4(-324) = 3600$ (1 Mark)
Roots are $\frac{-48 \pm 60}{2}$ (1 Mark)
i.e., 6, -54 (1/2 Mark)
(A) Given equation can be written as
$24(18 + x) - 24(18 - x) = 324 - x^2$ (1 Mark)
i.e., $x^2 + 48x - 324 = 0$ (1 Mark)
$D = 48^2 - 4(-324) = 3600$ (1 Mark)
Roots are $\frac{-48 \pm 60}{2}$ (1 Mark)
i.e., 6, -54 (1/2 Mark)