121
A quadratic equation $ax^2 + bx + c = 0$ has roots which are $1$ less than the roots of the quadratic equation $5x^2 - 2x - 3 = 0$. Find the roots of the equation $ax^2 + bx + c = 0$.
Show SolutionHide Solution↓
Roots of $5x^2 - 2x - 3 = 0$ are $1, -\frac{3}{5}$ (1+1 Mark)
Roots of equation $ax^2 + bx + c = 0$ are $0$ and $-\frac{8}{5}$ (1/2+1/2 Mark)
Roots of equation $ax^2 + bx + c = 0$ are $0$ and $-\frac{8}{5}$ (1/2+1/2 Mark)