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A $2$-digit number is such that the product of its digits is $18$. When $63$ is subtracted from the number, the digits interchange their places. Find the number.
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Let the required no. be $10x + y$
Here $xy = 18$ ---- (i)
$(10x + y) - 63 = 10y + x$
or $x - y = 7$ ---- (ii)
Solving (i) and (ii) to get
$x=9$ and $y=2$
Hence required number is $92$.
Here $xy = 18$ ---- (i)
$(10x + y) - 63 = 10y + x$
or $x - y = 7$ ---- (ii)
Solving (i) and (ii) to get
$x=9$ and $y=2$
Hence required number is $92$.