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Three unbiased coins are tossed simultaneously. Find the probability of getting :
(i) at least one head.
(ii) exactly one tail.
(iii) two heads and one tail.
(i) at least one head.
(ii) exactly one tail.
(iii) two heads and one tail.
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Total number of possible outcomes = $8$
(i) $P(\text{at least one head}) = \frac{7}{8}$
(ii) $P (\text{exactly one tail}) = \frac{3}{8}$
(iii) $P (\text{2 heads and one tail}) = \frac{3}{8}$
(i) $P(\text{at least one head}) = \frac{7}{8}$
(ii) $P (\text{exactly one tail}) = \frac{3}{8}$
(iii) $P (\text{2 heads and one tail}) = \frac{3}{8}$