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Probability of getting an irrational number at random from the numbers $\sqrt{3}$, $\sqrt{4}$, $3\sqrt{9}$, $3\sqrt{8}$, $\sqrt{5}$, $0$, $4^2$ is:
- (a)$0$
- (b)$\frac{4}{7}$
- (c)$\frac{3}{7}$
- (d)$1$
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Answer : (C) $\frac{3}{7}$