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A bag contains 4 red, 3 blue and 2 yellow balls. One ball is drawn at random from the bag. Find the probability that drawn ball is
(i) red (ii) yellow.
(i) red (ii) yellow.
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Total No of Balls=9
(i) P(drawn ball is red) = $\frac{4}{9}$
(ii) P(drawn ball is yellow) = $\frac{2}{9}$
(i) P(drawn ball is red) = $\frac{4}{9}$
(ii) P(drawn ball is yellow) = $\frac{2}{9}$