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A bag contains $3$ red balls, $5$ white balls and $7$ black balls. The probability that a ball drawn from the bag at random will be neither red nor black is :
- (a)$\frac{1}{3}$
- (b)$\frac{1}{5}$
- (c)$\frac{7}{15}$
- (d)$\frac{8}{15}$
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Sol.
(A) $\frac{1}{3}$
(A) $\frac{1}{3}$