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A bag contains $25$ balls. Some of them are yellow and others are green. One ball is drawn at random. If probability of getting a green ball is $\frac{3}{5}$, then find the number of yellow balls.
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Sol. P(getting a yellow ball) = $1$ – P(getting a green ball) (1 Mark)
$\frac{\text{Number of yellow balls}}{25} = 1 - \frac{3}{5} = \frac{2}{5}$ (1 Mark)
Number of yellow balls = $25 \times \frac{2}{5} = 10$
$\frac{\text{Number of yellow balls}}{25} = 1 - \frac{3}{5} = \frac{2}{5}$ (1 Mark)
Number of yellow balls = $25 \times \frac{2}{5} = 10$