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A bag contains $10$ red pens, out of which $3$ are defective and $8$ blue pens, out of which $4$ are defective. A pen is taken out from the bag at random. Find the probability that
(i) it is a defective pen,
(ii) it is a non-defective red pen.
(i) it is a defective pen,
(ii) it is a non-defective red pen.
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(i) $P (\text{getting a defective pen}) = \frac{7}{18}$ (1 Mark)
(ii) $P (\text{getting a non-defective red pen}) = \frac{7}{18}$ (1 Mark)
(ii) $P (\text{getting a non-defective red pen}) = \frac{7}{18}$ (1 Mark)