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Zeroes of the polynomial $p(y) = 7y^2 - \frac{11}{3}y - \frac{2}{3}$ are:
- (a)$\frac{2}{3}, -\frac{1}{7}$
- (b)$-\frac{2}{7}, -\frac{1}{3}$
- (c)$\frac{2}{1}, \frac{1}{7}$
- (d)$\frac{2}{3}, -\frac{1}{7}$
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(D) $\frac{2}{3}, -\frac{1}{7}$