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One zero of the polynomial $4x^2 - 12x + (2k + 1)$ is five times the other. Find the value of $k$.
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(b) Let zeroes of the polynomial be $\alpha$ and $5\alpha$
$\alpha + 5\alpha = \frac{12}{4} \Rightarrow \alpha = \frac{1}{2}$ (1/2 Mark)
$\alpha \times 5\alpha = \frac{2k + 1}{4}$ (1/2 Mark)
$\Rightarrow k = 2$ (1 Mark)
(b) Let zeroes of the polynomial be $\alpha$ and $5\alpha$
$\alpha + 5\alpha = \frac{12}{4} \Rightarrow \alpha = \frac{1}{2}$ (1/2 Mark)
$\alpha \times 5\alpha = \frac{2k + 1}{4}$ (1/2 Mark)
$\Rightarrow k = 2$ (1 Mark)