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If one zero of the polynomial $p(x) = (k − 1)x^2 − (4k + 1)x + 10$ is $5$, find the value of $k$.
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(b) Since, $5$ is the zero of the given polynomial
$\therefore (k – 1) (5)^2 – (4k + 1) (5) + 10 = 0$ (1 Mark)
$\Rightarrow k = 4$ (1 Mark)
(b) Since, $5$ is the zero of the given polynomial
$\therefore (k – 1) (5)^2 – (4k + 1) (5) + 10 = 0$ (1 Mark)
$\Rightarrow k = 4$ (1 Mark)