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If $\alpha, \beta$ are zeroes of the polynomial $3x^2 + 14x - 5$, then the value of $3\left(\frac{\alpha + \beta}{\alpha\beta}\right)$ is :
- (a)$\frac{14}{5}$
- (b)$\frac{42}{5}$
- (c)$-\frac{14}{5}$
- (d)$-\frac{42}{5}$
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(b) $\frac{42}{5}$