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If $\alpha, \beta$ are the zeroes of the polynomial $6x^2 - 5x - 4$, then $\frac{1}{\alpha} + \frac{1}{\beta}$ is equal to :
- (a)$\frac{5}{4}$
- (b)$-\frac{5}{4}$
- (c)$\frac{4}{5}$
- (d)$\frac{5}{24}$
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(b) $-\frac{5}{4}$