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Find the zeroes of the polynomial $r(x) = 4x^2 + 3x - 1$. Hence, write a polynomial whose zeroes are reciprocal of the zeroes of polynomial $r(x)$.
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$p(x) = 4x^2 + 3x - 1$. Zeroes are $\frac{1}{4}, -1$.
New zeroes $4, -1$.
Sum of new zeroes $= 4 + (-1) = 3$.
Product of zeroes $= 4 \times (-1) = -4$.
Required polynomial is $(x^2 - 3x - 4)$
New zeroes $4, -1$.
Sum of new zeroes $= 4 + (-1) = 3$.
Product of zeroes $= 4 \times (-1) = -4$.
Required polynomial is $(x^2 - 3x - 4)$