49
Find the zeroes of the polynomial $p(x) = 15x^2 – 19x + 6$.
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Solution:
(a) For zeroes $15x^2 – 19x + 6= 0$ (1 Mark)
Zeroes are $\frac{3}{5}$ and $\frac{2}{3}$ (1 Mark)
(a) For zeroes $15x^2 – 19x + 6= 0$ (1 Mark)
Zeroes are $\frac{3}{5}$ and $\frac{2}{3}$ (1 Mark)