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Find the zeroes of the polynomial $p(x) = x^2 + \frac{4}{3}x - \frac{4}{3}$.
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$\frac{1}{3}(3x^2 + 4x - 4) = \frac{1}{3}(3x^2 + 6x - 2x - 4) = \frac{1}{3}(3x - 2)(x + 2)$.
Zeroes are $\frac{2}{3}, -2$.
Zeroes are $\frac{2}{3}, -2$.