138
Determine a quadratic polynomial, sum and product of whose zeroes are $-10$ and $24$, respectively. Also, determine the zeroes of the polynomial so obtained.
Show SolutionHide Solution↓
Solution: Required polynomial is $x^2 + 10x + 24$
For zeroes: $x^2 + 10x + 24 = (x + 6) (x + 4)$
Zeroes are $-6, -4$
For zeroes: $x^2 + 10x + 24 = (x + 6) (x + 4)$
Zeroes are $-6, -4$