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Solve the following system of equations graphically :
$x+3y=6$ and $2x-3y = 12$
Also, find the area of the triangle formed by the lines $x+3y=6$,
$x = 0$ and $y = 0$.
$x+3y=6$ and $2x-3y = 12$
Also, find the area of the triangle formed by the lines $x+3y=6$,
$x = 0$ and $y = 0$.
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Ans.
(A) $x + 3y = 6$
$x$
$0$
$6$
$y$
$2$
$0$
$2x - 3y = 12$
$x$
$0$
$6$
$y$
$-4$
$0$
Correct Graph: (2 Marks)
Solution is $x = 6, y = 0$
(A) $x + 3y = 6$
$x$
$0$
$6$
$y$
$2$
$0$
$2x - 3y = 12$
$x$
$0$
$6$
$y$
$-4$
$0$
Correct Graph: (2 Marks)
Solution is $x = 6, y = 0$