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Solve the following system of equations for x and y :
$\frac{x}{2} + \frac{2y}{3} = - 1$ and $x - \frac{y}{3} = 3$
$\frac{x}{2} + \frac{2y}{3} = - 1$ and $x - \frac{y}{3} = 3$
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Solution : Solving the two equations to get $x = 2, y = - 3$