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If the system of linear equations
$2x + 3y = 7$ and $2ax + (a + b)y = 28$
have infinite number of solutions, then find the values of 'a' and 'b'.
$2x + 3y = 7$ and $2ax + (a + b)y = 28$
have infinite number of solutions, then find the values of 'a' and 'b'.
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system has infinite number of solutions
$\therefore \frac{2}{2a} = \frac{3}{a + b} = \frac{7}{28}$
$\Rightarrow \frac{1}{a} = \frac{1}{4} \Rightarrow a = 4$
and $a + b = 12 \Rightarrow b = 8$
$\therefore \frac{2}{2a} = \frac{3}{a + b} = \frac{7}{28}$
$\Rightarrow \frac{1}{a} = \frac{1}{4} \Rightarrow a = 4$
and $a + b = 12 \Rightarrow b = 8$