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Check whether the following pair of equations is consistent or not. If consistent, solve graphically $x + 3y = 6$, $3y - 2x = -12$.
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$x + 3y = 6$, $-2x + 3y = -12$. $\frac{a_1}{a_2} = \frac{1}{-2}$, $\frac{b_1}{b_2} = \frac{3}{3} = 1$ ($\frac{1}{2}$ mark). $\frac{a_1}{a_2} \neq \frac{b_1}{b_2}$. Hence the pair of equations is consistent ($\frac{1}{2}$ mark). Correct graph (1.5 marks). Solution is $(6, 0)$ or $x=6$ and $y=0$ ($\frac{1}{2}$ mark).