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(a) Solve the following system of equations graphically :
$x + 3y = 6; 2x - 3y = 12$
OR
(b) $x$ and $y$ are complementary angles such that $x : y = 1 : 2$. Express the given information as a system of linear equations in two variables and hence solve it.
$x + 3y = 6; 2x - 3y = 12$
OR
(b) $x$ and $y$ are complementary angles such that $x : y = 1 : 2$. Express the given information as a system of linear equations in two variables and hence solve it.
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Solution: (a) Correct graph of each equation
Solution is $x = 6, y = 0$ or $(6, 0)$
OR
(b) $x + y = 90^{\circ}$
$2x = y$
Solving to get $x = 30^{\circ}, y = 60^{\circ}$
Solution is $x = 6, y = 0$ or $(6, 0)$
OR
(b) $x + y = 90^{\circ}$
$2x = y$
Solving to get $x = 30^{\circ}, y = 60^{\circ}$