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The centre of a circle is at $(2, 0)$. If one end of a diameter is at $(6, 0)$, then the other end is at :
- (a)$(0,0)$
- (b)$(4,0)$
- (c)$(-2, 0)$
- (d)$(-6, 0)$
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Sol. (c) $(-2, 0)$
CBSE Class 10 Maths PYQ · Coordinate Geometry · Application · 1 Mark · March 2024 · Standard
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