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In the given figure, $\triangle ABC$ is an equilateral triangle. $AD$ is a median of the triangle joining the points $A \left(0, \frac{5\sqrt{3}}{2}\right)$, $D(0, 0)$. Points $B$ and $C$ are (in same order) :
- (a)$(-5, 0), (5, 0)$
- (b)$\left(-\frac{5}{2}, 0\right), \left(\frac{5}{2}, 0\right)$
- (c)$(-10, 0), (10, 0)$
- (d)$(-5\sqrt{3}, 0), (5\sqrt{3}, 0)$
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(B) $\left(-\frac{5}{2}, 0\right), \left(\frac{5}{2}, 0\right)$ (1 Mark)