63
Find the ratio in which the $y$-axis divides the line segment joining the points $(5,-6)$ and $(-1, -4)$.
Show SolutionHide Solution↓
Let $P(0, y)$ be the point on $y$ axis which divides AB in the ratio $k : 1$
$\frac{-k + 5}{k+ 1} = 0 \Rightarrow k = 5$
Ratio is $5: 1$
$\frac{-k + 5}{k+ 1} = 0 \Rightarrow k = 5$
Ratio is $5: 1$