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Find the length of the median through the vertex B of $\triangle ABC$ with vertices A($9$, $-2$), B($-3$, $7$) and C($-1$, $10$).
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Mid point of AC = $(4,4)$
Length of median from B to AC = $\sqrt{(4+3)^2 + (4-7)^2}$
$= \sqrt{7^2 + (-3)^2} = \sqrt{49+9} = \sqrt{58}$
Hence the length of median is $\sqrt{58}$ units
Length of median from B to AC = $\sqrt{(4+3)^2 + (4-7)^2}$
$= \sqrt{7^2 + (-3)^2} = \sqrt{49+9} = \sqrt{58}$
Hence the length of median is $\sqrt{58}$ units