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Find the coordinates of the points of trisection of the line segment joining the points A($-1, 4$) and B($-3,-2$).
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A $(-1,4)$ P Q B $(-3,-2)$
Let P and Q be the points of trisection of AB, therefore AP :PB = 1:2
Coordinates of P $= (\frac{1(-3)+2(-1)}{3}, \frac{1(-2)+2(4)}{3})$ (1 Mark)
$= (\frac{-5}{3}, 2)$ (1/2 Mark)
Q is the mid-point of PB (1 Mark)
Coordinates of Q $= (\frac{\frac{-5}{3}+(-3)}{2}, \frac{2+(-2)}{2})$ (1/2 Mark)
$= (\frac{-7}{3}, 0)$
Let P and Q be the points of trisection of AB, therefore AP :PB = 1:2
Coordinates of P $= (\frac{1(-3)+2(-1)}{3}, \frac{1(-2)+2(4)}{3})$ (1 Mark)
$= (\frac{-5}{3}, 2)$ (1/2 Mark)
Q is the mid-point of PB (1 Mark)
Coordinates of Q $= (\frac{\frac{-5}{3}+(-3)}{2}, \frac{2+(-2)}{2})$ (1/2 Mark)
$= (\frac{-7}{3}, 0)$