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Find a relation between $x$ and $y$ such that the point $P(x, y)$ is equidistant from the points $A(7, 1)$ and $B(3, 5)$.
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$PA= PB$
$\Rightarrow PA^2 = PB^2$
$(x - 7)^2 + (y -1)^2 = (x - 3)^2 + (y - 5)^2$
$\Rightarrow - 8x + 8y +16=0$ or $x-y-2=0$
$\Rightarrow PA^2 = PB^2$
$(x - 7)^2 + (y -1)^2 = (x - 3)^2 + (y - 5)^2$
$\Rightarrow - 8x + 8y +16=0$ or $x-y-2=0$